ypshimandClaude Haiku 5.5
7340f8c1a1
T형은 P1 문서의 고정 위치(2.196~12.000 m)·높이·11개를 써서 코핑 길이가 다르면 철근이 코핑 밖으로 나갔고, 다주형은 높은 계단 전체에 C15 하나만 두었다. 공통 규칙 (step-bars.ts): - 열마다(전·후열 단차가 있으면 각 쪽) 최저 상면 + h_16(100) 이상 구간이 계단, 경계는 mm 반올림 - 이웃보다 모두 높은 구간 C15(⊓), 나머지 계단 C16(L형, 낮은 쪽 다리, 높은 쪽으로 l_d 연장) - 폭 방향: T형은 주철근 내부 격자 하나 건너, 다주형은 상면 주철근 하나 건너 - 양쪽이 높은 계단은 RB-S01 알림, RB-M04 폐지. 꺾임은 편 좌표의 한 개(꺾은 철근) P1 문서값(C15 11 × 3852, C16 22 × 4070/4069, 137.5 · 10@250)을 그대로 재현한다. Co-Authored-By: Claude Haiku 5.5 <noreply@anthropic.com>
66 lines
3.2 KiB
TypeScript
66 lines
3.2 KiB
TypeScript
import { describe, expect, it } from 'vitest';
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import { buildPier } from '../src/core/geometry';
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import { rebarSummary } from '../src/core/rebar/summary';
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import { loadP1 } from './helpers';
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const { rows, warnings } = rebarSummary(buildPier(loadP1()));
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const count = (name: string) => rows.find((r) => r.name === name)!.count;
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describe('③ 철근표 요약 (P1)', () => {
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it('bearing blocks: S1 and S2 80 bars each', () => {
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expect(count('S1')).toBe(80);
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expect(count('S2')).toBe(80);
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});
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it('coping: C1–C8 12 each, C9 18, C10 9, C11 18, C13 20 (5 rows × 일자 2 + ㄷ 2), C12 8 (2 rows), C14 38, C15 11, C16 22', () => {
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for (const n of ['C1', 'C2', 'C3', 'C4', 'C5', 'C6', 'C7', 'C8']) expect(count(n)).toBe(12);
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expect(count('C9')).toBe(18);
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expect(count('C10')).toBe(9);
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expect(count('C11')).toBe(18);
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expect(count('C13')).toBe(20);
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expect(count('C12')).toBe(8);
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expect(count('C14')).toBe(38);
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expect(count('C15')).toBe(11);
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expect(count('C16')).toBe(22);
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});
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it('column: P1 230, P2 230, couplers 368, P3 39, P5 19, P4 8, P6 32', () => {
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expect(count('P1')).toBe(230);
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expect(count('P2')).toBe(230);
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expect(count('주철근 커플러')).toBe(368);
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expect(count('띠철근 커플러')).toBe(35);
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expect(count('P3')).toBe(39);
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expect(count('P5')).toBe(19);
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expect(count('P4')).toBe(8);
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expect(count('P6')).toBe(32);
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});
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it('footing (방향 교환): B1–B4 40 each, B5–B8 31 each, B10-1 16, B10-2 16, B11 30, B12 24 (k = 8)', () => {
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for (const n of ['B1', 'B2', 'B3', 'B4']) expect(count(n)).toBe(40);
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for (const n of ['B5', 'B6', 'B7', 'B8']) expect(count(n)).toBe(31);
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expect(count('B10-1')).toBe(16);
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expect(count('B10-2')).toBe(16);
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expect(count('B11')).toBe(30);
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expect(count('B12')).toBe(24);
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});
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it('B9: 306 bars (320 on the grid less 14 in the column zone); warnings: B6 needs a splice (13646 > 12000)', () => {
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expect(count('B9')).toBe(306);
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expect(warnings.map((w) => w.code)).toEqual(['I02', 'RB-S04', 'RB-F08']); // defaults are assumed values (I02); bearing embedment 619–669 < 882 (RB-S04)
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expect(warnings.find((w) => w.code === 'RB-F08')!.bar).toBe('B6');
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// B6 is split into two pieces (추천안): each piece is about half the 13646 bar plus half the lap.
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expect(rows.find((r) => r.name === 'B6')!.length!).toBeCloseTo(7776, 0);
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});
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it('lengths from the documents: C12 11746, C14 3447.5, C15 3852, C16 4070, P3 ≈ C_t + 1.3·l_d, P5 ≈ C_t', () => {
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// C12 has several lengths now: its straight bars are pieces (수정 2026-10-23); 11746 is the first 일자.
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expect(rows.find((r) => r.name === 'C12')!.pieces!.some((p) => p.length === 11746)).toBe(true);
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expect(rows.find((r) => r.name === 'C14')!.length).toBe(3447.5);
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expect(rows.find((r) => r.name === 'C15')!.length).toBe(3852);
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// C16 has two lengths (3·4구간), so the row lists them as pieces (2026-11-10).
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expect(rows.find((r) => r.name === 'C16')!.pieces).toEqual([{ length: 4070, count: 11 }, { length: 4069, count: 11 }]);
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expect(rows.find((r) => r.name === 'P5')!.length).toBeCloseTo(5657.7, 0);
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expect(rows.find((r) => r.name === 'P3')!.length!).toBeCloseTo(5657.7 + 1146.6, 0);
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});
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});
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