ypshimandClaude Haiku 5.5
cd18665d6a
- C4/C5 = distance from the coping edge to the bearing centre along the coping length, from the model; the drawing value is for comparison only. - A pair is a front and back bearing of the same order within their row. A pair with an eccentricity above 100 mm forbids 일체 (분리 first). - ② bearing card: read-only table of C4/C5 and the pair eccentricities. - The 일체 block model is not built yet. Co-Authored-By: Claude Haiku 5.5 <noreply@anthropic.com>
49 lines
2.3 KiB
TypeScript
49 lines
2.3 KiB
TypeScript
import { describe, expect, it } from 'vitest';
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import { buildPier, type BlockModel } from '../src/core/geometry';
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import { bearingEdgeDistances, PAIR_ECCENTRICITY_LIMIT_MM, pairEccentricities } from '../src/core/bearing-layout';
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import { loadP1 } from './helpers';
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const model = buildPier(loadP1());
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function block(no: number, row: '전열' | '후열', s: number): BlockModel {
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return { no, row, s, n: 0, k: 0, g: 0, bottom: 0, top: 0, padTop: 0, rowSkewDeg: 0 } as BlockModel;
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}
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describe('받침 배치 규칙 (승인 2026-10-26)', () => {
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it('C4 and C5 from the model: distances from each coping edge to the bearing centre (P1 ≈ 943 / 950 mm)', () => {
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const d = bearingEdgeDistances(model);
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expect(d).toHaveLength(10);
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const first = d.find((x) => x.no === 1 && x.row === '전열')!;
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expect(first.leftMm).toBeCloseTo(943, 0);
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expect(first.rightMm).toBeCloseTo(12000 - 943, 0);
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// the two ends of one bearing sum to the coping length
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for (const x of d) expect(x.leftMm + x.rightMm).toBeCloseTo(12000, 6);
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});
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it('the front and back bearings of one number are about 85 mm apart on P1, so 일체 is allowed', () => {
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const pairs = pairEccentricities(model.blocks);
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expect(pairs).toHaveLength(5);
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for (const p of pairs) {
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expect(p.eccentricityMm).toBeGreaterThan(80);
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expect(p.eccentricityMm).toBeLessThan(90);
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expect(p.allowed).toBe(true);
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}
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});
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it('an eccentricity above 100 mm forbids 일체 for that pair (분리 우선)', () => {
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expect(PAIR_ECCENTRICITY_LIMIT_MM).toBe(100);
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const pairs = pairEccentricities([block(1, '전열', 1.0), block(1, '후열', 1.12), block(2, '전열', 3), block(2, '후열', 3.09)]);
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expect(pairs.find((p) => p.frontNo === 1)!.allowed).toBe(false);
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expect(pairs.find((p) => p.frontNo === 2)!.allowed).toBe(true);
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});
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it('pairs by order within each row, so 전열 1 pairs with 후열 6 on P1 (numbers run on across the rows)', () => {
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const pairs = pairEccentricities(model.blocks);
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expect(pairs[0]).toMatchObject({ frontNo: 1, backNo: 6 });
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});
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it('a bearing left without a partner (the rows have different counts) is not paired', () => {
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expect(pairEccentricities([block(1, '전열', 1), block(2, '전열', 3), block(6, '후열', 1.05)])).toHaveLength(1);
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});
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});
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